HKDSE • Elective 3: Energy and Use of Energy • Buildings & air conditioning
Building Heat Gain, U-value & Air-Conditioner COP
Heat leaks into a cooled room through its envelope at a rate $Q/t = U A\,\Delta T$, and sunlight adds more through the window. An air conditioner must pump all of it back out, using electrical power $P = (Q/t)/\text{COP}$. Change the wall, window, shading and air conditioner and watch the energy bill respond.
Parameters
Hong Kong's recommended summer setting is 25.5 °C.
Wall material ($k$ in W m⁻¹ K⁻¹)
Fraction of solar radiation transmitted; sunshades, blinds and tinted glass lower $SC$.
$\text{COP} = Q_{\text{removed}} / W_{\text{electrical}}$. A Grade 1 energy-label unit has a higher COP.
Presets
Live readings
HKDSE formulae
Layers in series add their thermal resistances: $\frac{1}{U} = \frac{d_1}{k_1} + \frac{d_2}{k_2}$ (surface air films are ignored here).